3+x^2=100

Solution for 3+x^2=100 equation:

3+x^2=100

We move all terms to the left:

3+x^2-(100)=0

We add all the numbers together, and all the variables

x^2-97=0

a = 1; b = 0; c = -97;
Δ = b2-4ac
Δ = 02-4·1·(-97)
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{97}}{2*1}=\frac{0-2\sqrt{97}}{2}
=-\frac{2\sqrt{97}}{2}
=-\sqrt{97}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{97}}{2*1}=\frac{0+2\sqrt{97}}{2}
=\frac{2\sqrt{97}}{2}
=\sqrt{97}
$